Optimal. Leaf size=360 \[ -\frac{a^{3/4} e^4 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (63 \sqrt{a} B+25 A \sqrt{c}\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{30 c^{11/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{21 a^{5/4} B e^4 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{11/4} \sqrt{e x} \sqrt{a+c x^2}}-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}-\frac{21 a B e^4 x \sqrt{a+c x^2}}{5 c^{5/2} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2} \]
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Rubi [A] time = 0.404158, antiderivative size = 360, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {819, 833, 842, 840, 1198, 220, 1196} \[ -\frac{a^{3/4} e^4 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (63 \sqrt{a} B+25 A \sqrt{c}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 c^{11/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{21 a^{5/4} B e^4 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{11/4} \sqrt{e x} \sqrt{a+c x^2}}-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}-\frac{21 a B e^4 x \sqrt{a+c x^2}}{5 c^{5/2} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2} \]
Antiderivative was successfully verified.
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Rule 819
Rule 833
Rule 842
Rule 840
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{(e x)^{7/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{\int \frac{(e x)^{3/2} \left (\frac{5}{2} a A e^2+\frac{7}{2} a B e^2 x\right )}{\sqrt{a+c x^2}} \, dx}{a c}\\ &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2}+\frac{2 \int \frac{\sqrt{e x} \left (-\frac{21}{4} a^2 B e^3+\frac{25}{4} a A c e^3 x\right )}{\sqrt{a+c x^2}} \, dx}{5 a c^2}\\ &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2}+\frac{4 \int \frac{-\frac{25}{8} a^2 A c e^4-\frac{63}{8} a^2 B c e^4 x}{\sqrt{e x} \sqrt{a+c x^2}} \, dx}{15 a c^3}\\ &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2}+\frac{\left (4 \sqrt{x}\right ) \int \frac{-\frac{25}{8} a^2 A c e^4-\frac{63}{8} a^2 B c e^4 x}{\sqrt{x} \sqrt{a+c x^2}} \, dx}{15 a c^3 \sqrt{e x}}\\ &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2}+\frac{\left (8 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{-\frac{25}{8} a^2 A c e^4-\frac{63}{8} a^2 B c e^4 x^2}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{15 a c^3 \sqrt{e x}}\\ &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2}+\frac{\left (21 a^{3/2} B e^4 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{a}}}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{5 c^{5/2} \sqrt{e x}}-\frac{\left (a \left (63 \sqrt{a} B+25 A \sqrt{c}\right ) e^4 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{15 c^{5/2} \sqrt{e x}}\\ &=-\frac{e (e x)^{5/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 A e^3 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{7 B e^2 (e x)^{3/2} \sqrt{a+c x^2}}{5 c^2}-\frac{21 a B e^4 x \sqrt{a+c x^2}}{5 c^{5/2} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}+\frac{21 a^{5/4} B e^4 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{11/4} \sqrt{e x} \sqrt{a+c x^2}}-\frac{a^{3/4} \left (63 \sqrt{a} B+25 A \sqrt{c}\right ) e^4 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 c^{11/4} \sqrt{e x} \sqrt{a+c x^2}}\\ \end{align*}
Mathematica [C] time = 0.0690195, size = 127, normalized size = 0.35 \[ \frac{e^3 \sqrt{e x} \left (-25 a A \sqrt{\frac{c x^2}{a}+1} \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};-\frac{c x^2}{a}\right )+25 a A-21 a B x \sqrt{\frac{c x^2}{a}+1} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};-\frac{c x^2}{a}\right )+21 a B x+10 A c x^2+6 B c x^3\right )}{15 c^2 \sqrt{a+c x^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.043, size = 318, normalized size = 0.9 \begin{align*} -{\frac{{e}^{3}}{30\,x{c}^{3}}\sqrt{ex} \left ( 25\,A\sqrt{-ac}\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) a+126\,B\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticE} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ){a}^{2}-63\,B\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ){a}^{2}-12\,B{c}^{2}{x}^{4}-20\,A{c}^{2}{x}^{3}-42\,aBc{x}^{2}-50\,aAcx \right ){\frac{1}{\sqrt{c{x}^{2}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )} \left (e x\right )^{\frac{7}{2}}}{{\left (c x^{2} + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B e^{3} x^{4} + A e^{3} x^{3}\right )} \sqrt{c x^{2} + a} \sqrt{e x}}{c^{2} x^{4} + 2 \, a c x^{2} + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )} \left (e x\right )^{\frac{7}{2}}}{{\left (c x^{2} + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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